재료역학 7판 솔루션 Gere Down
재료역학 7판 솔루션 Gere Down
재료역학 7판 솔루션 Gere
재료역학 7판 솔루션 Gere
재료역학 7판 솔루션 GereDraft solutions manual for 7th edition of Mechanics of Materials, J. Gere & B. Goodno, 2009 -- see also updated Answers to Problems -- see also errata table NOTE: This file contains only solutions for those problems which are either new or revised versions of those in the 6e of this text; please consult the 6e ISM for any problem solutions not shown here
========================================================================================= SOLUTION Part (a) P1 = 1700 dAB = 1.25 tAB = 0.5 dBC = 2.25 tBC = 0.375
2 2 π ? ? dAB ? dAB ? 2? tAB ? ? ? AAB = 4
(
)
AAB = 1.178
σ AB =
P1 AAB
σ AB = 1.443 × 10
1443 psi
3
psi
Part (b)
2 2 π ? ? dBC ? dBC ? 2? tBC ? ? ? ABC = 4
(
)
ABC = 2.209
P2 = σ AB? ABC ? P1 P1 + P2
P2 = 1.488 × 10
1488 lbs 3
3
lbs
CHECK: Part (c) P2 = 2260 P1 + P2 σ AB
2
ABC
= 1.443 × 10
= ABC
P1 + P2 σ AB
= 2.744
green box contains answer in accordance with significant digits rule (Se
자료출처 : http://www.ALLReport.co.kr/search/Detail.asp?pk=11020330&sid=knp868group1&key=
[문서정보]
문서분량 : 520 Page
파일종류 : PDF 파일
자료제목 : 재료역학 7판 솔루션 Gere
파일이름 : 재료역학 7판 솔루션 Gere.pdf
키워드 : 재료역학,7판,솔루션,Gere
자료No(pk) : 11020330
재료역학 7판 솔루션 Gere
재료역학 7판 솔루션 Gere
재료역학 7판 솔루션 GereDraft solutions manual for 7th edition of Mechanics of Materials, J. Gere & B. Goodno, 2009 -- see also updated Answers to Problems -- see also errata table NOTE: This file contains only solutions for those problems which are either new or revised versions of those in the 6e of this text; please consult the 6e ISM for any problem solutions not shown here
========================================================================================= SOLUTION Part (a) P1 = 1700 dAB = 1.25 tAB = 0.5 dBC = 2.25 tBC = 0.375
2 2 π ? ? dAB ? dAB ? 2? tAB ? ? ? AAB = 4
(
)
AAB = 1.178
σ AB =
P1 AAB
σ AB = 1.443 × 10
1443 psi
3
psi
Part (b)
2 2 π ? ? dBC ? dBC ? 2? tBC ? ? ? ABC = 4
(
)
ABC = 2.209
P2 = σ AB? ABC ? P1 P1 + P2
P2 = 1.488 × 10
1488 lbs 3
3
lbs
CHECK: Part (c) P2 = 2260 P1 + P2 σ AB
2
ABC
= 1.443 × 10
= ABC
P1 + P2 σ AB
= 2.744
green box contains answer in accordance with significant digits rule (Se
자료출처 : http://www.ALLReport.co.kr/search/Detail.asp?pk=11020330&sid=knp868group1&key=
[문서정보]
문서분량 : 520 Page
파일종류 : PDF 파일
자료제목 : 재료역학 7판 솔루션 Gere
파일이름 : 재료역학 7판 솔루션 Gere.pdf
키워드 : 재료역학,7판,솔루션,Gere
자료No(pk) : 11020330
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